• Thumbnail for Ultrafilter
    In the mathematical field of order theory, an ultrafilter on a given partially ordered set (or "poset") P {\textstyle P} is a certain subset of P , {\displaystyle...
    20 KB (2,956 words) - 14:53, 25 July 2024
  • Thumbnail for Ultrafilter on a set
    In the mathematical field of set theory, an ultrafilter on a set X {\displaystyle X} is a maximal filter on the set X . {\displaystyle X.} In other words...
    47 KB (7,377 words) - 04:20, 9 April 2024
  • Thumbnail for Almost everywhere
    property true almost everywhere is sometimes defined in terms of an ultrafilter. An ultrafilter on a set X is a maximal collection F of subsets of X such that:...
    9 KB (1,261 words) - 12:11, 1 July 2024
  • Thumbnail for Hyperreal number
    be extended to an ultrafilter, but the proof uses the axiom of choice. The existence of a nontrivial ultrafilter (the ultrafilter lemma) can be added...
    33 KB (4,894 words) - 04:35, 23 July 2024
  • configurations in the X n {\displaystyle X_{n}} spaces employing an ultrafilter to bypass the need for repeated consideration of subsequences to ensure...
    14 KB (2,462 words) - 09:48, 17 May 2024
  • ideals. A variation of this statement for filters on sets is known as the ultrafilter lemma. Other theorems are obtained by considering different mathematical...
    15 KB (2,257 words) - 03:04, 29 November 2023
  • element i ∈ I {\displaystyle i\in I} (all of the same signature), and an ultrafilter U {\displaystyle {\mathcal {U}}} on I . {\displaystyle I.} For any two...
    18 KB (3,104 words) - 20:35, 16 August 2024
  • principal ultrafilter on X . {\displaystyle X.} Moreover, every principal ultrafilter on X {\displaystyle X} is necessarily of this form. The ultrafilter lemma...
    6 KB (834 words) - 00:10, 15 July 2024
  • to the following criterion: assuming the ultrafilter lemma, a space is compact if and only if each ultrafilter on the space converges. With this in hand...
    15 KB (2,094 words) - 09:49, 19 July 2024
  • then the ultrafilter U witnessing that κ is measurable will be in Vκ+2 and thus in M. So for any α < κ, we have that there exist an ultrafilter U in j(Vκ)...
    2 KB (271 words) - 06:29, 4 March 2024