1890 Belgian general election First party Second party Leader Auguste Beernaert Party Catholic Liberal Leader's seat Candidate for PM Seats before 98 seats 40 seats Seats won 29 40 Seats after 94 44 Seat change 4 4 Popular vote 17,253 20,829 Percentage 45.15% 54.51%
Partial general elections were held in Belgium on 10 June 1890.[ 1] [ 2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party , which won 94 of the 138 seats.[ 2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut , Limburg , Liège and East Flanders . Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[ 3]
Chamber of Representatives [ edit ] Party Votes % Seats Won Total +/– Liberal Party 20,829 54.51 40 44 +4 Catholic Party 17,253 45.15 29 94 –4 Belgian Labour Party 98 0.26 0 0 New Others 30 0.08 0 0 0 Total 38,210 100.00 69 138 0 Total votes 38,210 – Registered voters/turnout 59,452 64.27 Source: Mackie & Rose,[ 4] Sternberger et al .
The distribution of seats among the electoral districts was as follows:[ 5]